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发表于 7-7-2013 15:11:12|来自:新加坡
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原题:
Andy had $90 more than Sally ,when Andy and Sally each spent $30,Andy would have thrice as much as Sally had left.How much did Andy have at first?
答案是:¥165
解答:
一般有 more than/fewer than的差数关系 以及 twice/thrice等倍数关系时 鼓励孩子从倍数着手 一般先画倍数关系
引导孩子画图 小三开始需要练习
when Andy and Sally each spent $30,Andy would have thrice as much as Sally had left.
Andy (画三个单位的图,一般用三个boxes表示)
Sandy (同理,画一个box ) --> 两者差为两个boxes
Andy had $90 more than Sally ,when Andy and Sally each spent $30
两人花掉同样多的钱之后,差额保持不变 --> $90
过程: 3-1=2 (差为两倍)
$90 / 2 = $45 (一个box代表$45,即,在每人花了$30以后,Sally还剩$45,也就是一倍量)
$45 x 3 = $135 (在每人花了$30以后,Andy还剩$135, 即三倍量)
$135 + $30 = $165 (Andy's money at first)
注: 关于图形,应在Andy和Sally的三个boxes和一个box之前加一个大小不同于之前的box,代表各自花掉的$30。如果加在后面,孩子不容易做出比较。 |
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