再来发一道数学题，大家帮忙解题啊，谢谢了

973800qaz · 发表于 9-9-2013 16:07:47|来自：新加坡

觉得孩子翻译的题有点问题，所以把原文和他翻译的都呈上来，希望大家对他的翻译指正并解题。谢谢。

甲和乙参加了一个骑车比赛，甲的速度是20km/h，两个人的速度都没有变，在乙骑了一半时，甲在他3.5km 前，甲在1045 时到达终点，问乙几时到终点。

973800qaz · 发表于 9-9-2013 16:26:05|来自：新加坡

再发一个图片

suethuang · 发表于 9-9-2013 16:34:35|来自：新加坡

當乙到達終點時甲快了乙7公里。時間即為7\20h =21mins因此10：45加21mins =11:06

刀如水 · 发表于 9-9-2013 16:36:25|来自：新加坡

抄来的：

1.

2.
Suggested Answer:
3.5 x 2 = 7km(how much ahead is mei if she keep cycling when Lin finish the race)speed= 20km/h
7km= 7/20 X 1
=0.35 hr
=21 mins (time needed to be 7km ahead for mei)
Time when Lin complete the race = 10.45am+ 21mins
= 11.06am

3.
3.5 / 20 x 60 = 10.5 min
Mei took 10.5 min to travel 3.5 km (distance beyond half way mark).
So when Mei reached the half way mark,
Lin would need another 10.5 min to reach the half way mark,
i.e Lin was slower than Mei by 10.5 minutes for half the distance.
Hence for the race, Lin would be slower by 2 x 10.5 = 21 min.
21 min past 10.45 a.m. would be 11.06 a.m. (or use timeline)
Lin reach the finishing line at 11.06 a.m.